Typescript Deserialize Json To Class

Parse JSON String in TypeScript

  1. Typescript Deserialize Json To Class 9
  2. Typescript Deserialize Json To Class C
  3. Typescript Deserialize Json To Class
  4. Typescript Deserialize Json To Class 9
Typescript

In this tutorial, we will take a JSON string, and parse it to an object in TypeScript.

TypeScript: Working with JSON Sat, Mar 19, 2016. EDITS: Calling toString on Date is for illustrative purposes.; There’s a full commented example at the end. Use toJSON method as suggested by Schipperz. Apr 26, 2019 I started working with TypeScript about two years ago. Most of the time I read a JSON object from a remote REST server. This JSON object has all the properties of a TypeScript class. There is a question always buzz my head: How do I cast/parse the received JSON object to an instance of a corresponding class?

To parse a JSON string in TypeScript, you can use JSON.parse().

Example 1 – Parse JSON String

In this example, we will take a JSON string and parse it.

example.ts

Output

Example 2 – Parse JSON String to TypeScript Class Object

In this example, we will take a JSON string and parse it to a TypeScript class object.

Typescript Deserialize Json To Class 9

example.ts

The parsed JSON string is loaded to an object of specified TypeScript class. And we can access the properties of class object just like we access the elements of JSON object, using dot operator.

Typescript Deserialize Json To Class C

Output

Typescript Deserialize Json To Class

Conclusion

Typescript Deserialize Json To Class 9

In this TypeScript Tutorial, we learned how to parse a JSON string to a JSON object or to a custom TypeScript class object.